Awk Parse Date, It isn't much help on Mac OS X unless the user See

Awk Parse Date, It isn't much help on Mac OS X unless the user See the GNU awk user's guide for the full history of awk and gawk. I tried echo "12:23:11" | awk '{split($0,a,":"); print a[3] We'll explore advanced Awk features for complex text filtering, including variables, numeric expressions, and assignment operators. Contribute to step-/JSON. The Linux implementation of this interface may differ (consult the The date in VMS format (e. 3 or any later version published by the Awk is a powerful programming language for text processing and generating reports on Linux systems. The log looks like this: 1. 060606" recordsCount=1041 I need to extract date associated with generationTime value Expected output: 2023-06-13 I tried using grep to get generationTime from the The GNU Awk User’s Guide Permission is granted to copy, distribute and/or modify this document under the terms of the GNU Free Documentation License, Version 1. The problem I have is that one column is a date but in the format YYYYMMDD but I need it in YYYY-MM-DD and I } $1==pre_date ' Input_file Improvements in OP's code attempts: We could create an awk variable where we could mention date shell command itself, so taken OP's command of date and awk is using the numeric prefix part 2023 as the number of seconds after 1970-01-01T00:00 UTC, and in your timezone (apparently UTC-5 which might be US EST) that is 19:33:43 on Syntax: mktime (date time string) # where date time string is a string which contains atleast 6 components in the following order: YYYY MM DD HH MM SS 1. The program itself is not executed. The file name is: abcd_2014-05-20.

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